Wednesday, April 2, 2014
What is a Perfect Number ?
Tuesday, April 21, 2009
Integrating ROOT of tanx
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Tuesday, September 2, 2008
Logarithm-3
- loga(mn)=logam + logan
- loga(m/n) = logam - logan
- logamn = nlogam
- logbm = logam/logab
- (logab)(logba) = 1
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Monday, September 1, 2008
LOGARITHM-2
In my last article (Logarithm-1) I explained to you that what does it mean to take the logarithm of a number x to some base a. I explained there that when we take the logarithm of x to base a, we try to find out that to what power we must raise a to get x. In this sense if we have decided the value of a then for every value of x we will get a value y such that ay =x. And we write loga(x)=y.
For example let us take a=10.
Then following table illustrates the changing values of y with the changing values of x.
X | y= log10(x) | Explanation |
0.01 | -2 | 10-2=0.01 |
0.1 | -1 | 10-1=0.1 |
1 | 0 | 100=1 |
10 | 1 | 101=10 |
100 | 2 | 102=100 |
1000 | 3 | 103=1000 |
So we see that for every value of x , log10(x) gives an unique value of y. This kind of arrangement in mathematics is known as FUNCTION. Thus we can treat LOGARITHM as a function.
Therefore, now onwards we will treat y= loga(x) as a FUNCTION.
Rules for the values of base a, argument x and dependent variable y:
a ε (0,+∞) - {1}. Base a can take all positive values except 1.
x ε (0, +∞) ; Domain of logarithmic function.
y ε (- ∞,+∞) ; Range of logarithmic function.
Thursday, August 28, 2008
CONTACT-INFORMATION
J.P.Sinha: Teacher of Physics and Maths for IIT-JEE and PMT
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contact me (J.P.Sinha)on my mobile +91 9871 222 426 (it is a New Delhi mobile number).
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LOGARITHM-1
Author: J.P.Sinha, a teacher of Physics, Maths for IIT-JEE/PMT
These days, logarithm has strangely been dropped from the school syllabus of CBSE-system. Thus depriving the students from learning a very important skill in mathematics. Logarithm is used to expedite the solution of complicated arithmetical calculations. It is also an important FUNCTION that gives useful formulae in Integration and Differentiation.
DEFINITION:
We know 25=32 , so if we are asked 2?=32 then obviously our answer will be 5.
When be write 2?=32, we mean "to what power 2 must be raised to get 32?".
In mathematics normally we ask this question by using a different wording. We ask :
What is the logarithm of 32 to base 2?.And in symbols we express this question
as log2 32=?
Thus,
"to what power 2 be raised to give 32? ( i.e. 2?=32)"
and
" what is the logarithm of 32 to base 2? (i.e. log2 32=?)"
So, whenever we write " loga b =? " we mean "a?=b".
And if, loga b =c , then that will mean ac=b.
The expression loga b =c is read as " the logarithm of b to base a is c.