- loga(mn)=logam + logan
- loga(m/n) = logam - logan
- logamn = nlogam
- logbm = logam/logab
- (logab)(logba) = 1
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This blog is devoted to Maths.I will try to make this blog useful for the student community.Students can find here solutions to interesting sums.I will also be writing articles on various topics of maths in this.
In my last article (Logarithm-1) I explained to you that what does it mean to take the logarithm of a number x to some base a. I explained there that when we take the logarithm of x to base a, we try to find out that to what power we must raise a to get x. In this sense if we have decided the value of a then for every value of x we will get a value y such that ay =x. And we write loga(x)=y.
For example let us take a=10.
Then following table illustrates the changing values of y with the changing values of x.
X | y= log10(x) | Explanation |
0.01 | -2 | 10-2=0.01 |
0.1 | -1 | 10-1=0.1 |
1 | 0 | 100=1 |
10 | 1 | 101=10 |
100 | 2 | 102=100 |
1000 | 3 | 103=1000 |
So we see that for every value of x , log10(x) gives an unique value of y. This kind of arrangement in mathematics is known as FUNCTION. Thus we can treat LOGARITHM as a function.
Therefore, now onwards we will treat y= loga(x) as a FUNCTION.
Rules for the values of base a, argument x and dependent variable y:
a ε (0,+∞) - {1}. Base a can take all positive values except 1.
x ε (0, +∞) ; Domain of logarithmic function.
y ε (- ∞,+∞) ; Range of logarithmic function.
J.P.Sinha: Teacher of Physics and Maths for IIT-JEE and PMT
FOR any help or query relating to IIT-JEE preparation or PMT preparation
contact me (J.P.Sinha)on my mobile +91 9871 222 426 (it is a New Delhi mobile number).
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